Question

A uniform half metre ruler is freely pivoted at the 15cm mark and balanced horizontally when mass of 40g hangs at 20 cm mark make a clear sketch to show the forced and then calculate the mass of a half metre ruler

Answer 1

Answer:

Hello Dear.

Here is the answer---

•¶ Refers to the attachment for the Question.

Let the weight of the half metre rule be x gf and it acts at the 25 cm mark (centre of gravity).

Now,

•Acticlockwise moment = x * 4

•Clockwise moment = 20 * 21

In equilibrium,

Anticlockwise moment = Clockwise moment

•4x = 20*21

x = 105 gf.

Thus, the weight of the metre rule is 105 gf.

•We know, one gf is the force acting on the body of mass 1 grams, thus mass of the body is 105 grams.

°°°°°°°°°°°=°°°°°°°°°°°°°

•Hope it helps.•

Have a Marvelous Day ☺️

Answer 2

Answer:A mass of a rule is 53•3g

Explanation:firstly you draw a diagram of a half meter rule then you take the moments about fulcrum from the formula state (clockwise moment is equal to anticlockwise moment) their for the answer will be 53•3g