a uniform heavy rope is being pulled by a force 100 N find tension at its mid point
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Let the mass of the rope AB be m .
Acceleration of the rope = a = mF
Let the force be applied at the end A and the point at a distance x from point A be P .
Tension in the rope at a distance x from end A (at point P)
= Force required to move the remaining part with acceleration a
Linear mass density of the rod = lm
Mass of the remaing part i.e. part PB = lm(l−x)
Force required to move the remaining part = mass*acceleration
= lm(l−x)mF
Therefore , tension in the rope at a distance x from the
end at which the force is applied is F(ll−x).
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