A uniform horizontal rod of length 1.5 m is pivoted from
the middle such that it can rotate freely in vertical plane.
Two forces each of 100 N are applied at the two ends of
the rod in vertically upward and downward directions.
What is the magnitude of couple acting on this system?
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Answer:
Correct option is C)
Magnitude of force applied on each end = 10 N .
The moment of force τ = r × F. Hence in bothe the cases, moment of force is in the clockwise direction, and the moment of forces add to one another.
The magnitude of τ = 2 × 10 × 2 = 40 Nm in the clockwise direction.
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