a uniform iton bar of length 7m weighs 22.4kg how much dies the same bar of length 13m weigh
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Answered by
4
7 m ~ 22.4 kg
13 m ~ x kg
7/13 = 22.4/x
7x = 13 × 22.4
7x = 291.2
x = 291.2 : 7
x = 41.6 kg
13 m ~ x kg
7/13 = 22.4/x
7x = 13 × 22.4
7x = 291.2
x = 291.2 : 7
x = 41.6 kg
Answered by
3
First we will divide 22.4kg from 7m.
Then we will got 3.2kg weighs 1m uniform iton bar
After that we have to multiply 3.2kg with 13m
Then we will got 41.6kg which weighs 13 m uniform iton
Then we will got 3.2kg weighs 1m uniform iton bar
After that we have to multiply 3.2kg with 13m
Then we will got 41.6kg which weighs 13 m uniform iton
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