A uniform ladder of weight 800 N and of length 7m rests on ahorizontal ground and leans against a smooth vertical wall.the angle made by the ladder with the horizintal is 60 degrees .when a man of weight 600N stands on the ladder at a distance 4m from the top of the ladder , the ladder is at the.point of sliding . Determine the coefficient of friction between the ladder and the floor.
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Answer:
cofficient of friction b/w ladder and floor = 0.70
Explanation:
step 1 :
cos 30° = BC/AB = BC/7
BC = 6.06m
SIN 30° = AC/BC = AC/7
AC = 3.5m
Step 2 :
∑V = 0
Rf + Fw = 800+600
Rf + 0 = 1400N
Step 3 :
(800*6.06/2)+(600*3cos30°) = Rw * 3.5
2424+1558.84 = Rw * 3.5
3982.54 = Rw * 3.5
Rw = 1137.86N
Step 4 :
Ff = Rw
Мf * Rf = Rw
Мf = Rw/Rf = 1137.86/1400
Мf = 0.81
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