A uniform length of charge is lies on the circular arc as shown. The length of
the segment is 1 m and has a charge of +3.50 nC. What is the electric
potential at point P?
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Answer:
Now,
λ= LQ
λ= πR
Q/dq=λdx
=ππR/Q dx
Potential at P∫dV /1
=∫R/Kdq
=∫KKQR/dx
=∫0πR/Q×4πε0 Rdd/Vp
= 4πε0RQ/Vp
= 4πε0R /λ×πR
Vp = 4ε /0λ
Explanation:
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