Question

A uniform metal rod has Length L and cross sectional area A is pulled by applying two forces at opposite ends Young Modulus is Y what is net elongation ?

Answer 1

$\huge\mathcal\blue{\dag Answer \dag}$

Divide the rod into 2 parts of length 2l/m and l/m where the force F is acting.

Now solve the problem for the 2 rods separately.

Force acting on both sides of 2l/3 is 3F

Now total extension x is x=x1 +x2=8FL/3AY

Answer 2

Answer:

Divide the rod into 2 parts of length 2l/m and l/m where the force F is acting.

Now solve the problem for the 2 rods separately.

Force acting on both sides of 2l/3 is 3F

Now total extension x is x=x1 +x2=8FL/3AY