Question

A uniform metal rod of five metres in length and 90N in weight is suspended using two vertical strings attached at 50cm and 3.5m from one end. calculate the tension in each string. ​

Answer 1

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Answer 2

The tension in each string are 54 N and 36 N.

Explanation:

Given that,

Length of rod = 5 m

Weight = 90 N

We know that,

The total tension is

$T_{1}+T_{2}=90\ N$....(I)

We need to calculate the tension in first string

Using balance equation

$T_{1}=mg\cos\theta$

here, $\cos\theta=\dfrac{3}{5}$

Put the value into the formula

$T_{1}=90\times\dfrac{3}{5}$

$T_{1}=54\ N$

We need to calculate the tension in second string

Put the value of T₁ in equation (I)

$T_{2}=90-T_{1}$

$T_{2}=90-54$

$T_{2}=36\ N$

Hence, The tension in each string are 54 N and 36 N.

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Topic : tension

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