A uniform metallic wire has a resistance of, 18ohm and is bent into an equilateral triangle. Then, the resistance between any two vertices of the triangle is (a) 12ohm (b) 8ohm (c) 2ohm (d) 4ohm
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Answer:
The resistance in each part (side)= 6Ω
Between any two vertices (6Ω series 6Ω) parallel (6Ω)
equivalent resistance = (12) parallel 6Ω
= (12x6)/(18)
= 4Ω
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