A uniform metallic wire has a resistance of, 18ohm and is bent into an equilateral triangle. Then, the resistance between any two vertices of the triangle is (a) 12ohm (b) 8ohm (c) 2ohm (d) 4ohm
Answers
Answered by
0
Answer:
The resistance in each part (side)= 6Ω
Between any two vertices (6Ω series 6Ω) parallel (6Ω)
equivalent resistance = (12) parallel 6Ω
= (12x6)/(18)
= 4Ω
Similar questions