Question

a uniform meter rule of mass 100g is balanced on a fulcrum at mark 40cm by suspending an unknown mass m at the mark 30 cm . find the value of m.
please answer it at the latest.​

Answer 1

Answer:

Since, uniform metre rule of mass 100 g is balanced on a fulcrum at mark 40 cm. so, distance of c.o.m. of rule from balanced point is 10cm

Answer 2

Answer

Since, uniform metre rule of mass 100g is balanced on a fulcrum at mark 40 cm.

so, distance of c.o.m. of rule from balanced point is 10cm.

Net moment at balancing point should be zero.

So, m×20=100×10⟹m=50g

if m is moved to mark of 10cm,

then rule will tilt to the side where m is suspended.

Now, for balance this

50×30=100×10+50×(x−40)(x−40)=(1500−1000)/50=10cm

⟹X=50cm.

So, another 50g mass will be suspended at 50cm mark