A uniform meter scale of weight 50gf is balanced at 30cm mark when weight of 80gf and 60gf act at 5cm and 45cm mark respectively. What force must be applied at 20cm mark to balance the scale?
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Let a wt. of 80gf be placed at a distance x from 40cm mark.
Clock wise moments = Anticlock wise moment
(80 × x) + 50 × (50 – 40) = 100 × (40 – 5) 80x +500
= 3500 80x
= 3500 – 500
= 3000 x
= 3000/80
= 37.5cm
∴ A is at 40 + 37.5 = 77.5cm
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