A uniform meter scale rests horizontally on a knife edge at a 60cm mark, when a mass
of 25g is suspended from one end. (i) Draw diagram of the arrangement (ii) what is
the mass of the scale (iii) If 25g mass is shifted to 80cm mark then find the position of
knife edge so that the meter scale remain horizontal.
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Explanation:
sorry I can't right now I am outside home
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Answer:
Let M gram be the mass of the rule. Since density of the rule is uniform, its weight Mg will act at its middle point i.e., at the 50 cm mark (Fig.).
The weight of the rule produces an anti-clockwise moment about the knife-edge O. In order to balance it, 10 gram mass is to be suspended at the end B, to produce a clockwise moment.
From the principle of moments,
Anti-clockwise moment = Clockwise moment
Mg × (60 – 50) = 10 g × (100-60)
or Mg × 10 = 10 g × 40
∴ M = 40 gram
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