Question

A uniform metre rod, having a weight of 80 gf, has three weights of 20 gf, 50 gf, and 100 g.
suspended at the 25 cm, 20 cm and 80 em marks, respectively. Find the position of the wedge, if
the rod is balanced?
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Answer 1

Answer:

THE WEDGE IS BETWEEN 125 CM IS 62.5 CM AND 40 gf IS balanced each side

Explanation:

WEIGHTS( /2)= DISTANCE( /2)

20gf+50gf+10gf(/2)=25cm+20cm+80cm(/2)

80gf/2=125cm/2

40gf=62.5 in the each side

SO, THE WEDGE IS BEEN BALANCED

MARK IT AS BRAINLEST ANSWER OKKKK PLEASE