Physics, asked by moozashraf5802, 7 months ago

A Uniform Metre rule is pivoted at a 60 cm mark. It is balanced by suspending a weight of 100 gf at 80cm mark. What is the weight of the metre rule?

Answers

Answered by madeducators3
0

Given:

A uniform meter rule is pivoted at a  60 cm mark.

It is balanced by suspending a weight of 100 gf at 80 cm mark.

To Find:

The weight of the meter scale.

Solution:

A uniform meter scale is pivoted at a 60 cm mark.

Since the scale is uniform , hence the weight is uniformly distributed.

Hence the weight of scale can be assumed to be acting at the  center of mass of scale.

To balance the meter scale , moment about the pivot should be equal to 0.

weight suspended on scale to balance it = 100 gf at 80 cm mark.

that is 20 cm away from the pivot.

Hence the moment caused by weight suspended

M = F.r= 100(20) = 2000 gf cm.

Hence the moment of the weight of scale = 0

distance of force due to the weight of scale from the pivot = 10 cm (center of scale)

M = 2000 gf cm = F (10)

F = 200 gf

The weight of the meter scale= 200 gf .

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