Question

A uniform metre rule of mass 100 g is balanced on a fulcrum at mark 40cm by suspending an unknown mass 'm' at the mark 20cm. Find the value of m. ​

Answer 1

Explanation:

As 100g is balanced at fulcrum it will have a perpendicular distance of 40cm from itself and mass m will have 40−20=20cm distance.

Here moment of forces are equal that is balance each other.

Hence m×(40−20)=100×(50−40)

⇒m=100/2=50g.

Hence value of m is 50g.