Question

A uniform metre rule of mass 100g is balanced on a fulcrum at mark 30 cm by suspending an unknown mass ‘m’ at the mark 20 cm . 1) Find the value of m. 2) To which side the rule will tilt if the mass ‘m’ is moved to the mark 10 cm. 3) How can it be balanced by another mass of 50g​

Answer 1

Answer:

uniform metre rule of mass 100 g is balanced on a fulcrum at mark 40 cm. so, distance of c.o.m. of rule from balanced point is 10cm. Net moment at balancing point should be zero. if m is moved to mark of 10cm then rule will tilt to the side where m is suspende

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