Physics, asked by Anam1140, 8 months ago

A uniform metre rule of mass 120g suspended at its mid point from a spring balance, which is calibrated in newtown,has a stone, suspended at the 20cm mark, balanced by a 100g mass suspended on the 60cm mark. what is the reading on the spring balance?

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Answered by Anonymous
0

Answer:

hey mate

Explanation:

Brainly.in

What is your question?

1

Secondary School Physics 5 points

A uniform metre rule is pivoted at its midpoint.A weight of 50 gf is suspended at one end of it. Where should a weight of 100 gf be suspended to keep the rule horizontal?

Ask for details Follow Report by Sayansahu 06.04.2018

Answers

THE BRAINLIEST ANSWER!

Hi.

Here is your answer----

Diagram of your question is----

Units are in cm

-----------------------------------50cm---------------------------------------

weight is 50 gf

According to the principle of moments----

Sum of clockwise moments = Sum of Anticlockwise moments

50 x 50 = d x 100

d = 5 x 5

d = 25 cm

Thus, the weight must be suspended on the 25 cm mark to keep the meter rule in equilibrium.

Hope it will help u.

Have a nice day.

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