a uniform metre rule weighing 50g is supported at its ends and the two masses of 20g & 30g are suspended at 20cm and 90cm mark respectively. Find the reaction of the two supports
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Answer:
Explanation:
from Equilibrium,
clockwise moment=anticlockwise moment
W×15=75×g×25
m×g×15=75×g×25
∴=
15
75×25
=125g
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