A uniform metre scale 1 m long is suspended at 50 cm division. A known weight of 160 gwt is tied at 80 cm division and the scale is balanced by a weight of 240 gwt tied to the scale at a certain distance from the point of suspension on the opposite side. Calculate this distance.
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Hey!
Let the meter scales is balanced at X cm mark on the scale.
At the balancing condition, Anticlock wise moment must be equal to clock wise moment.
Clockwise moment, about the balancing point is
= moment by 80 gf
=80gf×(80−X)cm
=6400gfcm−80Xgfcm.....(1)
Anticlock wise moment about the balancing point is
= moment by 10 gf + moment by 50 gf
=10gf×(X−10)+50gf×(X−50)
=10Xgfc,−100gfcm+50Xgfcm−2500gfcm.....(2)
At the balancing condition, Clock wise at equilibrium = Anti clock wise moments.
6400−80X=100X−100+50X−2500
6400+2600=140X⇒140X=8000
⇒X=
140
8000
=64.28
Scale is balanced at 64.28 cm from the beginning.
HoPe it will be helpful ✌️
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