Question

A uniform metre scale attains rotational equilibrium about a point when a mass of 40 g is

suspended from 20 cm mark. Calculate the position of the fulcrum. (Take ,mass of the scale =

80g​

Answer 1

Refer to the attachment

hope it helps you

As 100 g is balanced at fulcrum it will have a perpendicular distance of 40 cm from itself and mass m will have 40 - 20 = 20 cm distance.

m=100/2=50g

Answer 2

Answer:

I hope it will help you

Explanation:

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