Question

a uniform metre scale is in equilibrium with its fulcrum at 30 cm and a weight of 40 Gf is 5 cm
(i) find the weight of the metre scale and
(ii) which of the following option is correct to keep the ruler in equilibrium when 40 Gf weight is shifted to 0 cm mark?(a) F shifted toward 0 CM or(b) F is shifted towards 100 CM mark


If we wronged the 2nd question how much marks would be cut out of 3 marks

Pls help pls pls pls help very important

Answer 1

Answer:

Part i)

Mass of the scale will be 50 Gf

Part ii)

F is shifted towards 0 cm mark

Explanation:

Part i)

As we know that scale is balanced at the position of 30 cm mark

So the torque due to weight of the scale is balanced by the torque due to external weight placed on the scale

So we have

$mg\times (50 - 30) = (0.040\times g)(30 - 5)$

$m(20) = (0.04)(25)$

$m = 50 gram$

Part ii)

When 40 Gf is shifted to 0 mark then its torque about the fulcrum will increase

In order to balance the torque the fulcrum distance must have to balance on the other side

So the F must be shifted towards 0 mark

#Learn

Topic : Torque balance

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