Question

A uniform metre scale of weight 50 gf is balanced at 30 cm mark when weight of 80 gf and 60 gf act at 5 cm mark and 45 cm respectively. What force must be applied at 20 cm mark to balance the metre scale? *

Answer 1

Answer:

Let a wt. of 80gf be placed at a distance x from 40cm mark. Clock wise moments = Anticlock wise moment (80 × x) + 50 × (50 – 40) = 100 × (40 – 5) 80x +500 = 3500 80x = 3500 – 500 = 3000 x = 3000/80 = 37.5cm ∴ A is at 40 + 37.5 = 77.5

Explanation:

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