a uniform path of width of 4cm runs around a square of side 11cm. find the area of the path and the outer and inner perimeter of the path
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Area of the path is 44cm, inner perimeter is 88cm
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Answer:
240 cm ^2
Step-by-step explanation:
Given
width = 8 cm
square = 11cm
11 cm + 8 cm =19 cm
Area of the path =(19×19) - (11 × 11)
= 361 - 121
= 240 cm ^2
outer perimeter = 4× 19 = 76 cm
inner perimeter = 4× 11 = 44 cm
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