Question

A uniform plank of weight 120 N rests on two stools as shown in Fig. 4.19. A weight of 80 N is placed on the plank, midway between the stools. Calculate:
a. the force acting on the stool at A,
b. the force acting on the stool at B

Please explain in detail... Thanks

Answer 1

Answer: (a) 88N and (b) 112N

This is your answer

Answer 2

The force acting on the stools of the $88N$ and $112N$.

Explanation:

A uniform plank of weight $120N$ rests on two stools as a midway between the stool.

$(80*1.25)+(120*1.5)=F_{B}*2.5$

$F_{B}=112N$

$(80*1.25)+(120*1.0)=F_{A}*2.5$

$F_{A}=88N$.