A uniform plank of weight 200 N and length 6 m is supported by a rope. If the breaking tension in the rope is 400 N. How far can a boy of
weight 400 N walk towards the support?
Answer it numerically plz, if possible send a pic. It's a numerical. do not give meaning less answer and for heaven's sake answer it numerically.
Answers
Answer:
4.5m
Explanation:
Force applied by the boy = Fm = 400N
Distance the boy can walk = Lm = ?
Force of the board = Fb = 200N
Distance to the center of gravity of the board = Lb = 3m
Breaking tension in the rope = Fr = 400N
Distance to the rope = Lr = 6m
According to the rule of equilibrium, all torques and forces on the board should be 0, so
(Fr)(Lr) - (Fm)(Lm) - (Fb)(Lb) = 0
(400)(6) - (400*Lm) - (200)(3) = 0
2400 - 600 = 400*Lm
400*Lm = 1800
Lm = 1800 / 400
Lm = 4.5m
Have a Great Day :)
Answer:
Given:
- weight of plank = 200 N and length 6 m is supported by a rope.
- breaking tension in the rope = 400 N.
- weight of boy = 400 N
To find:
- How far can a boy of weight 400 N walk towards the support?
Solution:
let , the distance that boy can walk towards the support = Lm
Force of the board = Fb = 200N
Breaking tension in the rope = Fr = 400N
Distance to the rope = Lr = 6m
Force applied by the boy = Fm = 400N
Distance to the center of gravity of the board = Lb = 3m
By the rule of equilibrium:
All torques and forces on the board should be 0,
=> (Fr)(Lr) - (Fm)(Lm) - (Fb)(Lb) = 0
=>(400)(6) - (400×Lm) - (200)(3) = 0
=> 2400 - 600 = 400×Lm
=> 400×Lm = 1800
=> Lm = 1800
400
=> Lm = 4.5m
hope it helps.