Question

A uniform plank of weight 200 N and length 6 m is supported by a rope as shown in the Figure. If the breaking tension in the rope is 400 N. How far can a boy of weight 400 N walk towards the support? (4.5 m) Klo = 3m K · 1 = 6m F = 400N F = 400N F = 200N​

Answer 1

Answer:

4.5m

Explanation:

Force applied by the boy = Fm = 400N

Distance the boy can walk = Lm = ?

Force of the board = Fb = 200N

Distance to the center of gravity of the board = Lb = 3m

Breaking tension in the rope = Fr = 400N

Distance to the rope = Lr = 6m

According to the rule of equilibrium, all torques and forces on the board should be 0, so

(Fr)(Lr) - (Fm)(Lm) - (Fb)(Lb) = 0

(400)(6) - (400*Lm) - (200)(3) = 0

2400 - 600 = 400*Lm

400*Lm = 1800

Lm = 1800 / 400

Lm = 4.5m

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Answer 2

see this attachment

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