Physics, asked by pritamporali2724, 1 year ago

A uniform plank of Young's modulus Y is moved over a
smooth horizontal surface by a constant horizontal force
F. The area of cross-section of the plank is A. the
compressive strain on the plank in the direction of the
force is
(1) F/AY (2) 2F/AY
(3)F/2AY
(4)3F/AY​

Answers

Answered by Smartyy3012
4
Y = Stress / Strain
Strain = F/AY
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