Question

A uniform ring of mass m with uniformly distributed charge q along its circumference of radius r is translating with speed v0 perpendicular to a uniform magnetic field as shown. The acceleration of the ring is (assuming gravity free space)

Answer 1

Answer:

electric field due to ring along its axis is given by,

where a is separation between observation point to centre of ring.

it is given that, a << R

so, a/R << 1 => a²/R² <<< 1

so, a²/R² + 1 ≈ 1 .....(1)

so,

or, [ from equation (1), ]

now, attractive force applied charge q

F = = mA, here A is acceleration.

so, A = kQqa/mR³

now applying formula, S = ut + 1/2 at²

S = 0 + 1/2 At²

a = 1/2 × kQqa/mR³ t²

or, mR³/kQq = t²

or, t = √{mR³/kQq}

hence ,time taken to reach the centre of ring will be

Answer 2

Answer:

here's the answer ll

hope it helps you