a uniform road of length 2 m is being balanced as shown in fig what is the magnitude of force at point T(Rw=90cm,Rv=60cm,Rt=10cm)
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Answer:
2.75 N
Explanation:
UT=50-10=40 cm
UV=60-50=10 cm
UW=90-50=40 cm
τT=τV+τW
─►UTxF=UVx3+UWx2
─►F=(10x3+2x40)/40
─►F=2.75 N
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