A uniform rod 1m long has masses of 100g and 40g at its ends. If it balances
30cm from one end, what is the weight of the rod?
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CM = 30 x 1 = 30Nm
ACM = 0.4 x 70 = 28Nm. + 20W
At equilibrium, CM = ACM
20W + 28= 30
20W = 30 - 28
20W = 2
W = 2/20
W = 0.1N
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