Question

A uniform rod 1m long has masses of 100g and 40g at its ends. If it balances
30cm from one end, what is the weight of the rod?

Answer 1

Answer:

As 100g is balanced at fulcrum it will have a perpendicular distance of 40cm from itself and mass m will have 40−20=20cm distance.

Here moment of forces are equal that is balance each other.

Hence m×(40−20)=100×(50−40)

⇒m=100/2=50g.

Hence value of m is 50g.

Explanation:

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