Physics, asked by harshith8143, 10 hours ago

A uniform rod AB is hinged about A and is free to rotate in ver sitical plane about an horizontal axis through A Initially it is held horizontally and released. Let a1 & a2 be the magnitudes of acceleration of the end B of the rod when the rod is horizontally and vertical respectively. Find a2/a1

Answers

Answered by bcsharma1945

1

Explanation:

R.E.F image

By parallel axis Theorem, MOL of rod

about hinge is

I0=12mL2+m(4L)2=487mL2

When rod reaches the vertical position

the center of mass of rod falls by

L/4

By consecration of energy

mg(4L)=21×I0w2

4mgL=21×487mL2w2

∴w=7L24g

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Answered by sahiltiwari919

0

Explanation:

it about your textbook query which u can find easily

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