Physics, asked by Weprashant51, 1 year ago

A uniform rod has a weight of 40. N and a length of 1.0 m. It is hinged to a wall (at the left end), and held in a horizontalposition by a vertical massless string (at the right end). What is the force in the string?

Answers

Answered by Fatimakincsem
12

The force in the string is 20 N.

Explanation:

Here in this case the sum of torque is equal to zero .

So , ∑τ = −r1 → × F1  →  + r2 → × F2− → = 0

⇒r1 → × F1 − → = r2 → × F2

⇒ τ2→ = 0⋅5 × 40 ×sin90°  = 20 N-m

Now the force on the string is the is.

F = torque /  length of the rod

  = τ2 / l

  = 20 N-m / 1 m = 20 N

Now find the three forces acting on the rod and this three forces are vertical .

Now the hinge force is "F" = Torque / length of the rod

                                            = 20 / 1 = 20 N

Hence the force in the string is 20 N.

Also learn more

What is the moment of 20 kg force if it acts on a point at a distance of 25 cm from  the point of rotation?

https://brainly.in/question/7948510          

Answered by paridhibansal2109
0

Answer:

yes it's the correct answer is

20N

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