A uniform rod has a weight of 40. N and a length of 1.0 m. It is hinged to a wall (at the left end), and held in a horizontalposition by a vertical massless string (at the right end). What is the force in the string?
Answers
Answered by
12
The force in the string is 20 N.
Explanation:
Here in this case the sum of torque is equal to zero .
So , ∑τ = −r1 → × F1 → + r2 → × F2− → = 0
⇒r1 → × F1 − → = r2 → × F2
⇒ τ2→ = 0⋅5 × 40 ×sin90° = 20 N-m
Now the force on the string is the is.
F = torque / length of the rod
= τ2 / l
= 20 N-m / 1 m = 20 N
Now find the three forces acting on the rod and this three forces are vertical .
Now the hinge force is "F" = Torque / length of the rod
= 20 / 1 = 20 N
Hence the force in the string is 20 N.
Also learn more
What is the moment of 20 kg force if it acts on a point at a distance of 25 cm from the point of rotation?
https://brainly.in/question/7948510
Answered by
0
Answer:
yes it's the correct answer is
20N
Similar questions