- A uniform rod is 4m long and weights 10kg.
If it is supported on a knife edge at one meter
from the end, what weight placed at that end
keeps the rod horizontal.
1) 8kg 2) 10kg 3) 12kg 4) 15kg
Answers
Answered by
8
The weight placed at other end to keep the rod horizontal will also be 10 Kg.
Explanation:
We are given that:
- Length of rod = 4 m
- Weight = 10 Kg
Solution:
Now apply the formula of torque balance:
τ x = w x τ
Torque gets cancelled on both sides.
Therefore;
x = w
Since w = 10 Kg
Hence x = 10 Kg
Thus the weight placed at other end to keep the rod horizontal will also be 10 Kg.
Answered by
0
Answer:
10 kg
Explanation:
mg(1)=10×1×(g)
m=10 kg
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