A uniform rod is suspended by means of two strings of length 0.10 m and 0.06 m attached to its two ends. The other two ends of the strings are tied to a nail. If tension in the first string is 30N,find the tension in the other.
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Answered by
5
draw the free body diagram . let the mass of the rod be m . And there are twon tension forces acting on it . Now tension in one string is 30 N and second string is T1 (suppose) . now , we get ,
30N + T1 - mg = 0 ( body is at rest)(equilibrium)
solving this you get T1 = (mg-30 ) N .
hope it helped .
Jasashmita1:
ur answer is wrong
listen , i have taken the value to t1 as 30 N , its given and i have just named the second tension as T1 , actually its the T2 only
but the answer is 18N
i am so sorry then .
would u please confirm the question ??
is the mass of rod given ???
hey , jasashmita , i am sorry
i gave wron solution . wait , i will upload the right one , i got the question wrong . so sorry .
it's ok
https://www.askiitians.com/forums/General-Physics/a-uniform-rod-is-suspended-by-means-of-two-strings_165279.htm
Answered by
4
.Soln-->let the rodAB be suspended by means of two strings AO and BO attached to the point O . Since the rod is in equilibrium tensions T1 ,T2 and weight W must meet at a point.applying trianglea law of vector addition in triangle OACT1/AO=T2/BO=W/OC therefore T1/T2=AO/BO GIVEN T1 =30NAO=0.10m,BO=0.06m30/T2 =0.10/0.06.......T2 = 18NSIR HOW T1/AO=T2/BO=W/OC
hope it helps u.....sorry ..it very conjusted....sorry for inconvenience
hope it helps u.....sorry ..it very conjusted....sorry for inconvenience
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