Question

a uniform rod of length 1m and mass1/2 kg rotates at angular speed 6rad/ sec about one of its end. The kinetic energy tof rod os
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Answer 1

Radius= length = 1m , mass =0.5kg , angular speed (omega)=6 rad/s


K.E =1/2mv^2
Linear velocity = angular velocity *radius
So V = 6*1 =6m/s

K.E =1/2*(0.5)*(6)^2
= 1/4*36
=9 joules .