Question

A uniform rod of length 4 m and mass
2√2 kg revolves with constant angular
velocity w about a vertical axis through a
smooth joint A at one extremity of the rod
so that it describes a cone of semi
vertical angle 53° as shown in the figure.
choose the INCORRECT statement(s).
(g=10m/s2)​

Answer 1

Thus the force acting on the rod is F = 8 x 10^-4 N

Explanation:

We are given that:

Length of rod = 4 m

Mass of rod = 2√2 kg

Solution:

F = 2 x uoI1 / 2 π R I2 x l

F = 2 x 2 x 10^-7 x 50 x 20 x 0.50 / 0.25

F = 8 x 10^-4 N

Thus the force acting on the rod is F = 8 x 10^-4 N