Question

A uniform rod of length 60 cm and mass 6kg is acted upon by two forces as shown in the diagram. The force exerted by 45cm part of the rod on 15cm part of the rod is​

Answer 1

Answer:

The answer is 27N.

Explanation:

As we know that

F = F1 + l1/L (F2 - F1)

Now put the values in this formula.

F = 45 + 45/60 (21 - 45)

F = 45 + 3/4 (-24)

F = 45 - 18  

F = 27 N

The force exerted by 45cm part of the rod on 15cm part of the rod is​ 27N.

Answer 2

Explanation:

21+6=27N

so the answer is 27N

I hope you understand

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