A uniform rod of length and mass M is at rest on a horizontal frictionless table. An impulse of magnitude I is applied to one end of the rod and perspendicular to it. The velocity of the center of mass is:
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Let v and w be the velocity and angular velocity of the rod finally.
Impulse= change in linear momentum
P=mv
L
O
=constant
0=mv
4
l
−I
CM
w
mv
4
l
=
12
1
ml
2
w
⟹w=
l
3v
=
ml
3P
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