Question

A uniform rod of length l is placed with one end in contact with the horizontal and is then inclined at an angle α to the horizontal and allowed to fall, without slipping at contact point. When it becomes horizontal, its angular velocity will be

Answer 1

Answer:

By conservation of energy PE of rod = Rotational PE

Mg

2

1

sinα=

2

1

lw

2

=

2

1

3

ml

2

w

2

w=

l

3gsinα

As here l−2l

w=

l

3gsinα

Here when it becomes horizontal

mgl=

2

1

3

ml

2

w

2

∴

l

6g