A uniform rod of length l is placed with one end in contact with the horizontal and is then inclined at an angle α to the horizontal and allowed to fall, without slipping at contact point. When it becomes horizontal, its angular velocity will be
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By conservation of energy PE of rod = Rotational PE
Mg21sinα=21lw2=213ml2w2w=l3gsinα
As here l−2l
w=l3gsinα
Here when it becomes horizontal
mgl=213ml2w2∴l6g
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