Physics, asked by paaji5625, 1 year ago

A uniform rod of mass m and length l is pivoted at a point a distance l/3

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Answered by vickygupta37
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A uniform rod of mass M and length L is pivoted at a point a distance L/3 from the top end. The rod is pulled back so that it makes an angle theta with the vertical and is then released.

1) Using Newton's 2nd law in rotational form, write but don't solve a differential equation in terms of M, L, and physical constants (if necessary), that can be used to determine the angular displacement theta as a function of time t.

2) Using this differential equation, show that the period of oscillation for the rod is given by T = 2pi(sqrt((2L)/(3g))).

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