Question

A uniform rod of mass M has an impulse applied at right angles to one end. If the other end begins to move with speed V, the magnitude of the impulse is?

Answer 1

Answer:

MV/2

Explanation:

Answer 2

Given that,

Mass of rod = M

Speed = V

Impulse :

Impulse is equal to the change in momentum.

Impulse is equal to the product of force and change in time.

In mathematically,

$\Delta p=F\times\Delta t$

Put the value of force in to the formula

$\Delta p=Ma\times \Delta t$

$\Delta p=M\dfrac{\Delta V}{\Delta t}\times\Delta t$

$\Delta p=M\Delta V$

$J=M(V_{f}-V_{i})$

Here, initial velocity is zero

So, the impulse will be

$J=MV$

Hence, The magnitude of the impulse is MV.