Physics, asked by wordak47, 1 year ago

A uniform rod of mass m is initially rotated about a vertical axis passing through its C.M. such that speed of
both ends is v in opposite direction and placed gently on a rough horizontal surface. If coefficient of friction
between rod and surface is u then rate of loss of kinetic energy just after the rod placed on surface is -
(2) umgy
(3) u mg
(4) 2 u mg
(1) umgev

Answers

Answered by adityasony061
24

Answer:

Explanation:H

Answered by bhuvna789456
1

Answer:

     The required block of minimum force is μ mg (Option 3).

Explanation:

  • Given:

                 Block of mass is 'm'

                 coefficient of friction ' μ'

           We have to apply a force that is just greater than static friction force on a body.

          So the required force is F= μ.N

                                                     = μ mg.

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