a uniform rod of turning is capable of turning free about a knife edge at 70 cm mark a mass of 10 g suspended at 15 cm and a mass of 0.15 KG substandard at 85 CM mark the rod exactly horizontal find the weight of the metre rod
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A uniform metre rod is capable of turning free about a knife edge at 70 cm mark. ... Suppose the mass of the metre rod is 'm'. According to the conservation of net torque for rotational equilibrium, 10 g ( 70 - 15 ) + mg ( 70 - 50 ) - 150 g ( 85 - 70 ) = 0 550 g + 20 mg - 2250 g = 0 20 mg = 2250 g -
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2250g
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