A uniform rodof length of 2 m mass 500g is pivoted at 60° of angle what is the kinetic energy
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At mean postion the total energy would be =>
mgl/2 + 0.5Iw^2 as we are unaware of w the value that is the total energy would be equals to => mglsin60/2
Hence the Total ENERGY would be => root(3)*0.5*10*2/4 => 5root(3) J
I hope its help you
mark brainliest
At mean postion the total energy would be =>
mgl/2 + 0.5Iw^2 as we are unaware of w the value that is the total energy would be equals to => mglsin60/2
Hence the Total ENERGY would be => root(3)*0.5*10*2/4 => 5root(3) J
I hope its help you
mark brainliest
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