Question

A uniform rope of length L is pulled by a constant force F. What is the tension in the rope at a distance l from the end where it is applied??

Answer 1

$\textbf{Hey.. mate here is yur ans...}$
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$\textbf{solution...}$

Let T be tension in the rope at point P, then

Acceleration of rope, a= F/M.

Equation of motion of part PB is F - T = (ml) a

==> T = F - (ml) a = F-[M/L] (l) [ F/M] = [ 1-l/L] F

Hope it helps u✌

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@Harshh☇☇

Answer 2

Hey mate ^_^

Net acceleration of of rope is:

a=F/m...1>

F−T =(mass of rope having length x)a    
{since mass of L =m so mass of length x =mLx}          

F−T=(m/L. x)a

Now putting the value of a from 1

F−T=(m/L. x)(F/m)

T=F(1−x/L)

#Be Brainly♥️