Question

A uniform rope of mass 2kg and length 4m connecting two blocks is placed on frictions
horizontal ground. The block of mass 3kg is pulled by a 24 N force as shown in the figure What
is tension in newtons at a point Im away from the 1 kg block?
24N
1kg
3kg​

Answer 1

Answer:

A 2.00-kg object undergoes an acceleration given by a = (6.00î+ ... a) Find the resultatnt force acting on the object ... Newton's Second Law : ∑ F = m a, with magnitude. ∑ ... b) If a rope is tied to the block and run vertically over a pulley, ... An object of mass m1 = 3.80-kg placed on a frictionless, horizontal.

Explanation:

Answer 2

Explanation:

The total mass of the system is m=2+1+1=4kg

The total mass of the system is m=2+1+1=4kgLet a be the acceleration of the system.

The total mass of the system is m=2+1+1=4kgLet a be the acceleration of the system.Thus, ma=F or 4a=8 or a=2m/s2

The total mass of the system is m=2+1+1=4kgLet a be the acceleration of the system.Thus, ma=F or 4a=8 or a=2m/s2The tension at A is TA= mass of left block ×acceleration =2×2=4N

The total mass of the system is m=2+1+1=4kgLet a be the acceleration of the system.Thus, ma=F or 4a=8 or a=2m/s2The tension at A is TA= mass of left block ×acceleration =2×2=4Nand tension at B is TB= (mass of left block + mass of string AB)× acceleration =(2+1)×2=6N