Question

a uniform rope of mass M and length L is placed on a smooth horizontal surface.A horizontal force is acting at one end of rope .Calculate tension in the rope at a distance x​

Answer 1

Answer:Tension will be F (L-x)/L

Explanation:

Answer 2

Answer:

$\frac{L-x}{L}F$

Explanation:

We are given that mass of uniform rope=M

Length of rope=L

A horizontal force acting at one end of rope

We have to find the tension in the rope at a distance x.

We know that F=ma

$a=\frac{F}{m}$

Let us consider the rope  at middle point distance x from the end of F.

Remaining length =L-x

Mass of L length of rope=M

Mass of (L-x) length of rope=$\frac{M}{L}(L-x)$

We know that tension=ma

Substitute the values then we get

$T=\frac{M}{L}(L-x)\times \frac{F}{M}=\frac{L-x}{L}F$

Hence, tension in the rope at a distance x=$\frac{L-x}{L}F$