a uniform See saw is 5 metre long. a boy weighing 50 kgf sits 2 metre from its centre.
where should another boy of 40 kg of mass sit to balance it
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Answer:
Each side is 2.5 m.The 40 kg boy is 1.5m from the end or 1m from the center.
40*1 = 25*x
x is the distance from the center to the girl.
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